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-2x=10x^2
We move all terms to the left:
-2x-(10x^2)=0
determiningTheFunctionDomain -10x^2-2x=0
a = -10; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-10)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-10}=\frac{0}{-20} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-10}=\frac{4}{-20} =-1/5 $
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